python实现简单神经网络算法

作者:由硬到软 时间:2021-03-22 07:03:16 

python实现简单神经网络算法,供大家参考,具体内容如下

python实现二层神经网络

包括输入层和输出层


import numpy as np

#sigmoid function
def nonlin(x, deriv = False):
 if(deriv == True):
   return x*(1-x)
 return 1/(1+np.exp(-x))

#input dataset
x = np.array([[0,0,1],
      [0,1,1],
      [1,0,1],
      [1,1,1]])

#output dataset
y = np.array([[0,0,1,1]]).T

np.random.seed(1)

#init weight value
syn0 = 2*np.random.random((3,1))-1

for iter in xrange(100000):
 l0 = x             #the first layer,and the input layer  
 l1 = nonlin(np.dot(l0,syn0))  #the second layer,and the output layer

l1_error = y-l1

l1_delta = l1_error*nonlin(l1,True)

syn0 += np.dot(l0.T, l1_delta)
print "outout after Training:"
print l1

import numpy as np

#sigmoid function
def nonlin(x, deriv = False):
 if(deriv == True):
   return x*(1-x)
 return 1/(1+np.exp(-x))

#input dataset
x = np.array([[0,0,1],
      [0,1,1],
      [1,0,1],
      [1,1,1]])

#output dataset
y = np.array([[0,0,1,1]]).T

np.random.seed(1)

#init weight value
syn0 = 2*np.random.random((3,1))-1

for iter in xrange(100000):
 l0 = x             #the first layer,and the input layer  
 l1 = nonlin(np.dot(l0,syn0))  #the second layer,and the output layer

l1_error = y-l1

l1_delta = l1_error*nonlin(l1,True)

syn0 += np.dot(l0.T, l1_delta)
print "outout after Training:"
print l1

这里,
l0:输入层

l1:输出层

syn0:初始权值

l1_error:误差

l1_delta:误差校正系数

func nonlin:sigmoid函数

python实现简单神经网络算法

可见迭代次数越多,预测结果越接近理想值,当时耗时也越长。

python实现三层神经网络

包括输入层、隐含层和输出层


import numpy as np

def nonlin(x, deriv = False):
 if(deriv == True):
   return x*(1-x)
 else:
   return 1/(1+np.exp(-x))

#input dataset
X = np.array([[0,0,1],
      [0,1,1],
      [1,0,1],
      [1,1,1]])

#output dataset
y = np.array([[0,1,1,0]]).T

syn0 = 2*np.random.random((3,4)) - 1 #the first-hidden layer weight value
syn1 = 2*np.random.random((4,1)) - 1 #the hidden-output layer weight value

for j in range(60000):
 l0 = X            #the first layer,and the input layer  
 l1 = nonlin(np.dot(l0,syn0)) #the second layer,and the hidden layer
 l2 = nonlin(np.dot(l1,syn1)) #the third layer,and the output layer

l2_error = y-l2    #the hidden-output layer error

if(j%10000) == 0:
   print "Error:"+str(np.mean(l2_error))

l2_delta = l2_error*nonlin(l2,deriv = True)

l1_error = l2_delta.dot(syn1.T)   #the first-hidden layer error

l1_delta = l1_error*nonlin(l1,deriv = True)

syn1 += l1.T.dot(l2_delta)
 syn0 += l0.T.dot(l1_delta)
print "outout after Training:"
print l2

import numpy as np

def nonlin(x, deriv = False):
 if(deriv == True):
   return x*(1-x)
 else:
   return 1/(1+np.exp(-x))

#input dataset
X = np.array([[0,0,1],
      [0,1,1],
      [1,0,1],
      [1,1,1]])

#output dataset
y = np.array([[0,1,1,0]]).T

syn0 = 2*np.random.random((3,4)) - 1 #the first-hidden layer weight value
syn1 = 2*np.random.random((4,1)) - 1 #the hidden-output layer weight value

for j in range(60000):
 l0 = X            #the first layer,and the input layer  
 l1 = nonlin(np.dot(l0,syn0)) #the second layer,and the hidden layer
 l2 = nonlin(np.dot(l1,syn1)) #the third layer,and the output layer

l2_error = y-l2    #the hidden-output layer error

if(j%10000) == 0:
   print "Error:"+str(np.mean(l2_error))

l2_delta = l2_error*nonlin(l2,deriv = True)

l1_error = l2_delta.dot(syn1.T)   #the first-hidden layer error

l1_delta = l1_error*nonlin(l1,deriv = True)

syn1 += l1.T.dot(l2_delta)
 syn0 += l0.T.dot(l1_delta)
print "outout after Training:"
print l2

来源:http://blog.csdn.net/stoneyyhit/article/details/52335468

标签:python,神经网络
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