python实现五子棋游戏
作者:ArthurCaoMH 时间:2021-09-24 13:52:37
本文实例为大家分享了python实现五子棋游戏的具体代码,供大家参考,具体内容如下
话不多说,直接上代码:
全部工程文件,在GitHub:五子棋
效果预览:
#!/usr/bin/env python3
#-*- coding:utf-8 -*-
import pygame
from pygame.locals import *
from sys import exit
import numpy
background_image = 'qipan.png'
white_image = 'white.png'
black_image = 'black.png'
def WhoWin(x,y,darray):
num1,num2,num3,num4 = 0,0,0,0
#判断上下左右左上右上左下右下8个方向
i = x-1
while(i>=0):
if darray[i][y] == 1:
num1+=1
i -= 1
else:
break
i = x+1
while i<19:
if darray[i][y] == 1:
num1+=1
i += 1
else:
break
j =y-1
while (j >= 0):
if darray[x][j] == 1:
num2 += 1
j -= 1
else:
break
j = y + 1
while j < 19:
if darray[x][j] == 1:
num2 += 1
j += 1
else:
break
i,j = x-1,y-1
while(i>=0 and j>=0):
if darray[i][j] == 1:
num3 += 1
i -= 1
j -= 1
else :
break
i, j = x + 1, y + 1
while (i < 19 and j < 19):
if darray[i][j] == 1:
num3 += 1
i += 1
j += 1
else:
break
i, j = x + 1, y - 1
while (i >= 0 and j >= 0):
if darray[i][j] == 1:
num4 += 1
i += 1
j -= 1
else:
break
i, j = x - 1, y + 1
while (i < 19 and j < 19):
if darray[i][j] == 1:
num4 += 1
i -= 1
j += 1
else:
break
#五子胜
if num1>=4 or num2>=4 or num3 >= 4 or num4 >= 4:
return True
else:
return False
#初始化
pygame.init()
#屏幕、背景图、白黑子转换
screen = pygame.display.set_mode((584, 584), RESIZABLE, 32)
background = pygame.image.load(background_image).convert()
white = pygame.image.load(white_image).convert_alpha()
black = pygame.image.load(black_image).convert_alpha()
#标题画图字体
screen.blit(background, (0,0))
font = pygame.font.SysFont("arial", 40);
pygame.display.set_caption('五子棋')
#zeros()返回19行19列的数组
white_luodian = numpy.zeros((19,19))
black_luodian = numpy.zeros((19,19))
#设置棋盘的所有点的坐标
qipan_list = [(30+i*29-12,30+j*29-12) for i in range(19) for j in range(19)]
#默认黑子先手,转换下棋
transW_B = True
#游戏主循环
while True:
for event in pygame.event.get():
if event.type == QUIT:
exit()
if event.type == MOUSEBUTTONDOWN:
x,y = pygame.mouse.get_pos()
if 30 <= x <= 554 and 30 <= y <= 554 and ((x - 30) % 29 <= 12 or (x - 30) % 29 >= 17) and (
(y - 30) % 29 <= 12 or (y - 30) % 29 >= 17):
#四舍五入
m = int(round((x-30)/29))
n = int(round((y-30)/29))
#结果分析
if transW_B:
transW_B = not transW_B
screen.blit(black, qipan_list[19*m+n])
black_luodian[n][m] = 1
if WhoWin(n,m,black_luodian):
screen.blit(font.render('Black chess player wins!', True, (0, 0, 0),(0,229,238)), (120, 280))
else:
transW_B = not transW_B
screen.blit(white, qipan_list[19 * m + n])
white_luodian[n][m] = 1
if WhoWin(n,m,white_luodian):
screen.blit(font.render('White chess player wins!', True, (255, 255, 255),(0,229,238)), (120, 280))
qipan_list[19*m+n] = ''
pygame.display.update()
来源:https://blog.csdn.net/ArthurCaoMH/article/details/88376553
标签:python,五子棋
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