Python实现新版正方系统滑动验证码识别
作者:狂野小青年 时间:2022-11-08 09:14:32
Python实现新版正方系统滑动验证码识别算法和方案
步骤一:点击数据分析
点击滑动按钮,将发送一个请求到 /zfcaptchaLogin
请求内容
"type": "verify"
"rtk": "6cfab177-afb2-434e-bacf-06840c12e7af"
"time": "1624611806948"
"mt": "W3sieCI6OTY1LCJ5IjoxNjksInQiOjE2MjQ2MTE4MDY4Njh9LHsieCI6OTY1LCJ5IjoxNjksInQiOjE2MjQ2MTE4MDY5NDh9XQ=="
"instanceId": "zfcaptchaLogin"
"extend": "eyJhcHBOYW1lIjoiTmV0c2NhcGUiLCJ1c2VyQWdlbnQiOiJNb3ppbGxhLzUuMCAoTWFjaW50b3NoOyBJbnRlbCBNYWMgT1MgWCAxMF8xNV83KSBBcHBsZVdlYktpdC81MzcuMzYgKEtIVE1MLCBsaWtlIEdlY2tvKSBDaHJvbWUvOTEuMC40NDcyLjEwNiBTYWZhcmkvNTM3LjM2IiwiYXBwVmVyc2lvbiI6IjUuMCAoTWFjaW50b3NoOyBJbnRlbCBNYWMgT1MgWCAxMF8xNV83KSBBcHBsZVdlYktpdC81MzcuMzYgKEtIVE1MLCBsaWtlIEdlY2tvKSBDaHJvbWUvOTEuMC40NDcyLjEwNiBTYWZhcmkvNTM3LjM2In0="
通过 base64 解密 mt和 extend 得出解密的数值
# mt
[{"x":965,"y":169,"t":1624611806868},{"x":965,"y":169,"t":1624611806948}]
# extend
{"appName":"Netscape","userAgent":"Mozilla/5.0 (Macintosh; Intel Mac OS X 10_15_7) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/91.0.4472.106 Safari/537.36","appVersion":"5.0 (Macintosh; Intel Mac OS X 10_15_7) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/91.0.4472.106 Safari/537.36"}
mt 为用户的点击行为,x为X轴上的值,y为Y轴上的值,t为时间戳。通过大量点击分析,发现x值最小值为 950,得出950 为 X轴的起点,y值随机无固定值。
extend 为请求头部内容
步骤二:滑动验证码图像分析,计算滑动距离x值
将图像灰度化,通过getpixel可以获取图像某一点的颜色值, 颜色值越高代表图像越浅,所以寻找纵向连续50个像素点均是 getpixel(x+1, y) > getpixel(x, y)(X轴=x 比 X轴=x+1 颜色浅)
并扫描图像,当x=130、扫描高度=50时,的颜色比x+1时深。
from PIL import Image
import matplotlib.pyplot as plt
import numpy as np
scanf_height= 50 # 扫描的高度
img = Image.open("zfcaptchaLogin.png")
def contrast(imgl, x, y,scanf_height):
# 黄框颜色值比红框颜色值浅的个数
count = 0
for i in range(scanf_height):
if imgl.getpixel((x+1, y+i)) > imgl.getpixel((x, y+i)):
count += 1
# 当 count = scanf_height, 代表黄条区域 整体 红条区域 颜色值浅,则是验证码框位置
return count
def scanf(img):
imgx, imgy = img.size
imgl = img.convert('L') # 图像灰度化
plt.yticks([])
plt.xticks([i for i in range(0, imgx, 25)])
plt.imshow(img)
plt.pause(0.5)
for y in range(0, imgy-scanf_height, 10):
plt.pause(0.01)
plt.clf()
plt.yticks([])
plt.xticks([i for i in range(0, imgx, 25)])
plt.imshow(imgl, cmap=plt.cm.gray)
for x in range(1, imgx-1, 1):
plt.pause(0.0001)
plt.plot([x-1,x-1], [y, y+scanf_height], color='white')
plt.plot([x,x], [y, y+scanf_height], color='red')
plt.plot([x+1,x+1], [y, y+scanf_height], color='yellow')
count = contrast(imgl, x,y, scanf_height)
plt.title('count: {}'.format(count) )
print("x,y=[{}, {}], 黄条区域值比红条区域颜色值浅的个数:{}".format(x,y, count))
if count == scanf_height:
return
scanf(img)
plt.show()
优化代码计算x,y值
import json
import random
import time
from io import BytesIO
from PIL import Image
class ZfCaptchaRecognit(object):
def __init__(self, img_path):
self.img = Image.open(img_path)
def _get_xy(self):
# 计算 x,y 值
def _is_dividing_line(img_l, x, y):
for n in range(50):
# 寻找纵向连续50个像素点均是 X=x 比 X=x+1 颜色深
if y + n >= img_l.size[1] or x >= img_l.size[0] - 1:
return False
if img_l.getpixel((x + 1, y + n)) - img_l.getpixel((x, y + n)) < 2:
return False
return True
img_l = self.img.convert("L")
for x in range(img_l.size[0]):
for y in range(img_l.size[1]):
if _is_dividing_line(img_l, x, y):
return (x, y)
def show_tag(self):
# 展示 切分点
X, Y = self._get_xy()
img2 = Image.new("RGB", self.img.size, (255, 255, 255))
for x in range(self.img.size[0]):
for y in range(self.img.size[1]):
pix = self.img.getpixel((x, y))
img2.putpixel((x, y), pix)
if x == X or y == Y:
img2.putpixel((x, y), 225)
img2.save("show_tag.png")
img2.show()
captcha = ZfCaptchaRecognit("zfcaptchaLogin.png")
captcha.show_tag()
步骤三:生成提交参数
通过 步骤一得出x值最小为950,y值无规律
则提交参数mt的大致格式数据是
[{
"x":950+ 滑动距离 + 浮动值, # 浮动值的范围通过分析提交参数得出在10~20内
"y":random.randint(150, 190), # 无规律,暂定150到190范围内
"t":int(time.time() * 1000)}, # 时间戳
...]
获取mt 参数
import json
import random
import time
from io import BytesIO
from PIL import Image
class ZfCaptchaRecognit(object):
def __init__(self, img_stream):
obj = BytesIO(img_stream)
self.img = Image.open(obj)
def _get_xy(self):
...
def generate_payload(self):
base_x = 950
X, Y = self._get_xy()
payloads = [{"x": base_x + random.randint(5, 20), "y": random.randint(150, 190), "t": int(time.time() * 1000)}]
for i in range(random.randint(15, 30)):
# 在上一个参数基础下浮动
last_payload = payloads[-1].copy()
payloads[0]["x"] += random.choice([0] * 8 + [1, -1] * 2 + [2, -2])
last_payload["t"] += random.randint(1, 20)
last_payload["y"] += random.choice([0] * 8 + [1, -1] * 2 + [2, -2])
payloads.append(last_payload)
payloads[-1]["x"] = base_x + random.randint(10, 20) + X
return json.dumps(payloads)
captcha = ZfCaptchaRecognit("zfcaptchaLogin.png")
captcha. generate_payload()
来源:https://blog.csdn.net/veloi/article/details/115416495
标签:Python,滑动验证码,识别
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