python如何获取apk的packagename和activity

这篇文章主要介绍了python如何获取apk的packagename和activity,文中通过示例代码介绍的非常详细，对大家的学习或者工作具有一定的参考学习价值,需要的朋友可以参考下

实现代码如下：

# 找出packagename和activity
import os
import re
class packagename_activity:
 def get_packagename(self, path):
   aapt = []
   os.system(f'aapt dump badging {path}> ../xc_logs/AaptLog.txt')
   with open('../xc_logs/AaptLog.txt', 'rb') as f:
     p1 = "package: name='(.+?)'"
     results1 = re.finditer(pattern=p1, string=f.readline().decode('utf-8'))
     for r in results1:
       packagename = r.group(1)
       aapt.append(packagename)
     p2 = "launchable-activity: name='(.+?)'"
     st = str(f.readlines())
     results2 = re.findall(p2, st)
     activity = results2[0]
     aapt.append(activity)
   return aapt
if __name__ == '__main__':
 a=packagename_activity()
 b=a.get_packagename('../xc_apk/wangyiyunyinyue.apk')
 print(b)

来源：https://www.cnblogs.com/badbadboyyx/p/12163494.html