Python开发桌面小程序功能

当使用桌面应用程序的时候，
有没有那么一瞬间，
想学习一下桌面应用程序开发？
建议此次课程大家稍作了解不要浪费太多时间，
因为没有哪家公司会招聘以为Python程序员开发桌面程序吧？

开发环境：

• Python 3.6

• Pycharm

代码

界面设置

导入模块

import tkinter as tk

实例化一个窗体对象

root = tk.Tk()

标题

root.title('计算器')

大小以及出现的位置

root.geometry("295x280+150+150")

透明度

root.attributes("-alpha", 0.9)

背景

root["background"] = "#ffffff"

标签

lable1 = tk.Label(root, textvariable=result_num, width=20, height=2, font=('宋体', 20), justify='left', background='#ffffff', anchor='se')

布局

lable1.grid(padx=4, pady=4, row=0, column=0, columnspan=4)

按钮

button_clear = tk.Button(root, text='C', width=5, font=('宋体', 16), relief='flat', background='#C0C0C0', command=lambda: clear())
button_back = tk.Button(root, text='←', width=5, font=('宋体', 16), relief='flat', background='#C0C0C0', command=lambda: back())
button_division = tk.Button(root, text='/', width=5, font=('宋体', 16), relief='flat', background='#C0C0C0', command=lambda: operator('/'))
button_multiplication = tk.Button(root, text='x', width=5, font=('宋体', 16), relief='flat', background='#C0C0C0', command=lambda: operator('*'))
button_clear            .grid(padx=4, row=1, column=0)
button_back             .grid(padx=4, row=1, column=1)
button_division         .grid(padx=4, row=1, column=2)
button_multiplication   .grid(padx=4, row=1, column=3)
button_seven = tk.Button(root, text='7', width=5, font=('宋体', 16), relief='flat', background='#FFDEAD', command=lambda: append_num('7'))
button_eight = tk.Button(root, text='8', width=5, font=('宋体', 16), relief='flat', background='#FFDEAD', command=lambda: append_num('8'))
button_nine = tk.Button(root, text='9', width=5, font=('宋体', 16), relief='flat', background='#FFDEAD', command=lambda: append_num('9'))
button_subtraction = tk.Button(root, text='—', width=5, font=('宋体', 16), relief='flat', background='#C0C0C0', command=lambda: operator('-'))
button_seven        .grid(padx=4, row=2, column=0)
button_eight        .grid(padx=4, row=2, column=1)
button_nine         .grid(padx=4, row=2, column=2)
button_subtraction  .grid(padx=4, row=2, column=3)
button_four = tk.Button(root, text='4', width=5, font=('宋体', 16), relief='flat', background='#FFDEAD', command=lambda: append_num('4'))
button_four.grid(padx=4, pady=4, row=3, column=0)
button_five = tk.Button(root, text='5', width=5, font=('宋体', 16), relief='flat', background='#FFDEAD', command=lambda: append_num('5'))
button_five.grid(padx=4, row=3, column=1)
button_six = tk.Button(root, text='6', width=5, font=('宋体', 16), relief='flat', background='#FFDEAD', command=lambda: append_num('6'))
button_six.grid(padx=4, row=3, column=2)
button_addition = tk.Button(root, text='+', width=5, font=('宋体', 16), relief='flat', background='#C0C0C0', command=lambda: operator('+'))
button_addition.grid(padx=4, row=3, column=3)
button_one = tk.Button(root, text='1', width=5, font=('宋体', 16), relief='flat', background='#FFDEAD', command=lambda: append_num('1'))
button_one.grid(padx=4, row=4, column=0)
button_two = tk.Button(root, text='2', width=5, font=('宋体', 16), relief='flat', background='#FFDEAD', command=lambda: append_num('2'))
button_two.grid(padx=4, row=4, column=1)
button_three = tk.Button(root, text='3', width=5, font=('宋体', 16), relief='flat', background='#FFDEAD', command=lambda: append_num('3'))
button_three.grid(padx=4, row=4, column=2)
button_equal = tk.Button(root, text='=', width=5, height=3, font=('宋体', 16), relief='flat', background='#C0C0C0', command=lambda: equal())
button_equal.grid(padx=4, row=4, rowspan=5, column=3)
button_zero = tk.Button(root, text='0', width=12, font=('宋体', 16), relief='flat', background='#FFDEAD', command=lambda: append_num('0'))
button_zero.grid(padx=4, pady=4, row=5, column=0, columnspan=2)
button_decimal = tk.Button(root, text='.', width=5, font=('宋体', 16), relief='flat', background='#FFDEAD', command=lambda: append_num('.'))
button_decimal.grid(padx=4, row=5, column=2)

现在得出界面效果

功能

添加数字

def append_num(i):
   lists.append(i)
   result_num.set(''.join(lists))

选择运算符号

def operator(i):
   if len(lists) > 0:
       if lists[-1] in ['+', '-', '*', '/']:
           lists[-1] = i
       else:
           lists.append(i)
       result_num.set(''.join(lists))

清零

def clear():
   lists.clear()
   result_num.set(0)

退格

def back():
   del lists[-1]
   result_num.set(lists)

等号

def equal():
   a = ''.join(lists)
   end_num = eval(a)
   result_num.set(end_num)
   lists.clear()
   lists.append(str(end_num))

定义一个列表收集输入的内容

lists = []
result_num = tk.StringVar()
result_num.set(0)

最后运行代码，效果如下图

先试试

运算得出结果

来源：https://blog.csdn.net/m0_67575344/article/details/124026574