python实现一组典型数据格式转换

本文实例为大家分享了一组典型数据格式转换的python实现代码，供大家参考，具体内容如下

有一组源数据，第一行会是个日期数据，第二行标明字段，再接下来是两行数据行。

1018 14:31:30.193
Type Succ Fail
sour_sm 1308 1205
data_sm 2205 3301
1019 16:32:30.201
Type Succ Fail
data_sm 3308 2206
data_sm 1765 1105
1020 18:00:00.203
Type Succ Fail
sour_sm 7804 1105
data_sm 2976 1300

要转换成数据

Time               Type    Succ Fail  Total
1018 14:31:30.193  sour_sm 1308 1205  2513
1018 14:31:30.193  data_sm 2205 3301  5506
1019 16:32:30.201  data_sm 3308 2206  5514
1019 16:32:30.201  data_sm 1765 1105  2870
1020 18:00:00.203  sour_sm 7804 1105  8909
1020 18:00:00.203  data_sm 2976 1300  4276

这个时候可以使用Python来处理，代码如下:

# coding = utf-8
fd = open(r"output.txt", "w", encoding="utf-8")
fd.write("％s\t\t\t\t％s\t％s\t％s\t％s\n" ％ ("Time", "Type", "Succ", "Fail", "Total"))

with open(r"data.txt", "r", encoding="utf-8") as fd1:
lines = fd1.readlines()
time1 = lines[0::4]
data1 = lines[2::4]
data2 = lines[3::4]
for (i, line) in enumerate(time1):
Time = line.strip()
Type_1 = data1[i].strip().split()[0]
Succ_1 = data1[i].strip().split()[1]
Fail_1 = data1[i].strip().split()[2]
Total_1 = str(int(Succ_1) + int(Fail_1))
Type_2 = data2[i].strip().split()[0]
Succ_2 = data2[i].strip().split()[1]
Fail_2 = data2[i].strip().split()[2]
Total_2 = str(int(Succ_2) + int(Fail_2))
fd.write("％s\t％s\t％s\t％s\t％s\n" ％ (Time, Type_1, Succ_1, Fail_1, Total_1))
fd.write("％s\t％s\t％s\t％s\t％s\n" ％ (Time, Type_2, Succ_2, Fail_2, Total_2))
fd.close()

生成文件格式如下，基本上满足了需求。

来源：https://blog.csdn.net/Jerry_1126/article/details/84930210