python 删除指定时间间隔之前的文件实例

遍历指定文件夹下的文件，根据文件后缀名，获取指定类型的文件列表；根据文件列表里的文件路径，逐个获取文件属性里的“修改时间”，如果“修改时间”与“系统当前时间”差值大于某个值，则删除该文件。

#!/usr/bin/env python
# -*- coding: utf-8 -*-
"""Document: Remove Synctoycmd sync expired .tmp files"""
import os
import time
import datetime
def diff():
 '''time diff'''
 starttime = datetime.datetime.now()
 time.sleep(10)
 endtime = datetime.datetime.now()
 print "time diff: ％d" ％ ((endtime-starttime).seconds)
def fileremove(filename, timedifference):
 '''remove file'''
 date = datetime.datetime.fromtimestamp(os.path.getmtime(filename))
 print date
 now = datetime.datetime.now()
 print now
 print 'seconds difference: ％d' ％ ((now - date).seconds)
 if (now - date).seconds > timedifference:
   if os.path.exists(filename):
     os.remove(filename)
     print 'remove file: ％s' ％ filename
   else:
     print 'no such file: ％s' ％ filename
FILE_DIR = 'D:/'
if __name__ == '__main__':
 print 'Script is running...'
 #diff()
 while True:
   ITEMS = os.listdir(FILE_DIR)
   NEWLIST = []
   for names in ITEMS:
     if names.endswith(".txt"):
       NEWLIST.append(FILE_DIR + names)
   #print NEWLIST
   for names in NEWLIST:
     print 'current file: ％s' ％ (names)
     fileremove(names, 10)
   time.sleep(10)
 print "never arrive..."

来源：https://blog.csdn.net/zsy19881226/article/details/72638036