python实现图像拼接

本文实例为大家分享了python实现图像拼接的具体代码，供大家参考，具体内容如下

1.待拼接的图像

2. 基于SIFT特征点和RANSAC方法得到的图像特征点匹配结果

3.图像变换结果

4.代码及注意事项

import cv2
import numpy as np

def cv_show(name, image):
cv2.imshow(name, image)
cv2.waitKey(0)
cv2.destroyAllWindows()

def detectAndCompute(image):
image = cv2.cvtColor(image, cv2.COLOR_BGR2GRAY)
sift = cv2.xfeatures2d.SIFT_create()
(kps, features) = sift.detectAndCompute(image, None)
kps = np.float32([kp.pt for kp in kps]) # 得到的点需要进一步转换才能使用
return (kps, features)

def matchKeyPoints(kpsA, kpsB, featuresA, featuresB, ratio = 0.75, reprojThresh = 4.0):
# ratio是最近邻匹配的推荐阈值
# reprojThresh是随机取样一致性的推荐阈值
matcher = cv2.BFMatcher()
rawMatches = matcher.knnMatch(featuresA, featuresB, 2)
matches = []
for m in rawMatches:
 if len(m) == 2 and m[0].distance < ratio * m[1].distance:
  matches.append((m[0].queryIdx, m[0].trainIdx))
kpsA = np.float32([kpsA[m[0]] for m in matches]) # 使用np.float32转化列表
kpsB = np.float32([kpsB[m[1]] for m in matches])
(M, status) = cv2.findHomography(kpsA, kpsB, cv2.RANSAC, reprojThresh)
return (M, matches, status) # 并不是所有的点都有匹配解，它们的状态存在status中

def stich(imgA, imgB, M):
result = cv2.warpPerspective(imgA, M, (imgA.shape[1] + imgB.shape[1], imgA.shape[0]))
result[0:imageA.shape[0], 0:imageB.shape[1]] = imageB
cv_show('result', result)

def drawMatches(imgA, imgB, kpsA, kpsB, matches, status):
(hA, wA) = imgA.shape[0:2]
(hB, wB) = imgB.shape[0:2]
# 注意这里的3通道和uint8类型
drawImg = np.zeros((max(hA, hB), wA + wB, 3), 'uint8')
drawImg[0:hB, 0:wB] = imageB
drawImg[0:hA, wB:] = imageA
for ((queryIdx, trainIdx),s) in zip(matches, status):
 if s == 1:
  # 注意将float32 --> int
  pt1 = (int(kpsB[trainIdx][0]), int(kpsB[trainIdx][1]))
  pt2 = (int(kpsA[trainIdx][0]) + wB, int(kpsA[trainIdx][1]))
  cv2.line(drawImg, pt1, pt2, (0, 0, 255))
cv_show("drawImg", drawImg)

# 读取图像
imageA = cv2.imread('./right_01.png')
cv_show("imageA", imageA)
imageB = cv2.imread('./left_01.png')
cv_show("imageB", imageB)
# 计算SIFT特征点和特征向量
(kpsA, featuresA) = detectAndCompute(imageA)
(kpsB, featuresB) = detectAndCompute(imageB)
# 基于最近邻和随机取样一致性得到一个单应性矩阵
(M, matches, status) = matchKeyPoints(kpsA, kpsB, featuresA, featuresB)
# 绘制匹配结果
drawMatches(imageA, imageB, kpsA, kpsB, matches, status)
# 拼接
stich(imageA, imageB, M)

来源：https://blog.csdn.net/qiao_lili/article/details/89736237