python 实现批量xls文件转csv文件的方法

引言：以前写的一个批量xls转csv的python简单脚本，用的是python2.7

#coding=utf-8
import os
import time
import logging
import xlrd
import csv
#xls文件存放路径
INPUTPATH= u"D:\\lsssl\\桌面\\xls文件"
#生成的csv文件存放路径
OUTPATH = u"D:\\lsssl\桌面\\csv"
class changeCenter:
def __init__(self):
 pass
def getvalue(self,filename):
 self.mData = []
 xlsfile=xlrd.open_workbook(filename)
 table = xlsfile.sheet_by_index(0)#sheet1
 rownum = table.nrows #行
 colsnum = table.ncols #列
 for i in range(0,rownum):
  row = []
  for j in range(0,colsnum):
   value = table.cell_value(i,j)
   if not isinstance(value,float):
    value = value.encode('gbk')#非数字转一下码
   row.append(value)
  self.mData.append(tuple(row))
def write(self, path, filename):
 if not os.path.exists(path):
  os.makedirs(path)
 csvfile = file("tmp","wb")
 writer = csv.writer(csvfile)
 writer.writerows(self.mData)
 csvfile.close()
if os.path.exists(os.path.join(path,filename+".old")):
  os.remove(os.path.join(path,filename+".old"))
 if os.path.exists(os.path.join(path,filename)):
  os.rename(os.path.join(path,filename),os.path.join(path,filename+".old"))
 os.rename('tmp', os.path.join(path,filename))
 logging.info("write file finish")
 print "write",filename," finish"
def handleExcel():
files,dirs,root = readFilename(INPUTPATH)
for fi in files:
 strstock = os.path.join(INPUTPATH,fi)
 if os.path.exists(strstock):
  st = changeCenter()
  st.getvalue(strstock)
  name = fi.replace(".xls","")
  st.write(OUTPATH, name+".csv")
 else:
  print strstock+" don't exist"
#获取某个路径下的所有文件
def readFilename(file_dir):
for root, dirs, files in os.walk(file_dir):
 return files,dirs,root
if __name__ == '__main__':
handleExcel()

来源：https://blog.csdn.net/lishenluo/article/details/79244176