Python判断telnet通不通的实例

这个跟ping那个差不多，ping的那个脚本就是通过这个改了下，大体一致，不过telnet的不需要判断返回的字符串。快一些

这里具体需要telnet的ip是需要自己向定义好的数组中写的

我这里加了一个定时，是7200秒，也就是2小时

行了，上代码吧：

#!/usr/bin/env python
# coding: utf8

import telnetlib
import time
import codecs
import os

# telnet host
def telnetdo(host, statusFile):
status1 = 'telnet success'
status2 = 'telnet faild'
for ipAdd in host:
# get now time
nowTime = time.strftime('％Y-％m-％d ％H:％M:％S',time.localtime(time.time()))
try:
 t = telnetlib.Telnet(ipAdd, port=23, timeout=1)
 writeToText(nowTime, ipAdd, status1, statusFile)
except:
 writeToText(nowTime, ipAdd, status2, statusFile)

# write status information to txt
def writeToText(nowTime, ipAdd, status, statusFile):
s_text = 'TIME:' + nowTime + '\t' + 'IP:' + ipAdd + '\t' + 'STATUS:' + status + '\r\n'

if '0' == judgeFile(statusFile):
with open(statusFile, 'a') as f:
 f.write(s_text)
 f.close()
if '1' == judgeFile(statusFile):
with open(statusFile, 'w') as f:
 f.write(s_text)
 f.close()

# Determine whether statusFile exists
# 0: exists
# 1: no exists
def judgeFile(statusFile):
if os.path.exists(statusFile):
return '0'
else:
return '1'

if __name__ == "__main__":
host = ['192.168.1.254', '192.168.1.100']
# write file
statusFile = '/root/telnetStatus.txt'
i = 7200
while i:
telnetdo(host, statusFile)
time.sleep(2)
i = i - 1

结果会存在/root下面

来源：https://blog.csdn.net/qq_21911403/article/details/77585146