Python3调用微信企业号API发送文本消息代码示例

本文主要向大家分享了Python3调用微信企业号API发送文本消息示例的有关代码，具体如下：

#!/usr/bin/env python
# -*- coding:utf-8 -*-
import urllib.request
import json
import sys
import logging
touser = '@all'
agentid = 0
corpid = 'wx5aef2da956514535'
corpsecret = 'Co17m_OPlvE8Q4P2RKKwtq5oIA3p42xGUZEvCHBI8S0'
url = 'https://qyapi.weixin.qq.com'
subject = sys.argv[2]
message = sys.argv[3]
logging.basicConfig(level=logging.DEBUG, filename='E:\Python_project\Scripts\my.log',
         format='％(asctime)s - ％(levelname)s: ％(message)s')
class Weixin:
 def __init__(self, url, corpid, corpsecret):
   token_url = '％s/cgi-bin/gettoken?corpid=％s&corpsecret=％s' ％ (url, corpid, corpsecret)
   self.token = json.loads(urllib.request.urlopen(token_url).read().decode())['access_token']
 def send_message(self, url, data):
   send_url = '％s/cgi-bin/message/send?access_token=％s' ％ (url, self.token)
   self.respone = urllib.request.urlopen(urllib.request.Request(url=send_url, data=data)).read()
   x = json.loads(self.respone.decode())['errcode']
   if x == 0:
     logging.debug('Successfully ％s  ％s' ％ (subject, message))
     return 'Succesfully'
   else:
     logging.debug('Failed ％s  ％s' ％ (subject, message))
     return 'Failed'
 def messages(self, subject, message):
   values = {
     "touser": touser,
     "msgtype": 'text',
     "agentid": agentid,
     "text": {'content': subject + message},
     "safe": 0
   }
   return self.send_message(url, bytes(json.dumps(values), 'utf-8'))
if __name__ == '__main__':
 obj = Weixin(url, corpid, corpsecret)
 ret = obj.messages(subject, message)

来源：http://www.cnblogs.com/postgres/p/6942812.html