C#实现程序开机启动的方法

本文实例讲述了C#实现程序开机启动的方法。分享给大家供大家参考，具体如下：

//此方法把启动项加载到注册表中
//获得应用程序路径
string strAssName = Application.StartupPath + @"\" + Application.ProductName + @".exe";
//获得应用程序名
string ShortFileName = Application.ProductName;
RegistryKey rgkRun = Registry.LocalMachine.OpenSubKey("SOFTWARE\\Microsoft\\Windows\\CurrentVersion\\Run", true);
if (rgkRun == null)
{
 rgkRun = Registry.LocalMachine.CreateSubKey("SOFTWARE\\Microsoft\\Windows\\CurrentVersion\\Run");
}
rgkRun.SetValue(ShortFileName, strAssName);
//此删除注册表中启动项
//获得应用程序名
string ShortFileName = Application.ProductName;
RegistryKey rgkRun = Registry.LocalMachine.OpenSubKey("SOFTWARE\\Microsoft\\Windows\\CurrentVersion\\Run", true);
if (rgkRun == null)
{
 rgkRun = Registry.LocalMachine.CreateSubKey("SOFTWARE\\Microsoft\\Windows\\CurrentVersion\\Run");
}
rgkRun.DeleteValue(ShortFileName, false);

希望本文所述对大家C#程序设计有所帮助。