java map转Multipart/form-data类型body实例
作者:qq_33770498 时间:2023-04-19 13:16:18
我就废话不多说了,大家还是直接看代码吧!
public static String mapToTxt(Map<String,String> fieldMap, Map<String,File> fileMap,String fileName) throws Exception{
Random random = new Random();
int j;
String getLine = "\r\n";
String fileType = "Content-Type: application/octet-stream";
String doubleBar = "--";
biaoshi = "----WebKitFormBoundary";
StringBuffer sb = new StringBuffer();
for(int i = 0; i < 16;i++){
j = random.nextInt(MULTIPART_CHARS.length-2)+2;
sb.append(MULTIPART_CHARS[j]);
}
biaoshi = biaoshi + sb.toString();
StringBuffer stringBuffer = new StringBuffer();
for (Map.Entry<String,String> entity:fieldMap.entrySet()) {
String name = "Content-Disposition: form-data; name=\""+entity.getKey()+"\"";
stringBuffer.append(doubleBar+biaoshi);
stringBuffer.append(getLine);
stringBuffer.append(name);
stringBuffer.append(getLine);
stringBuffer.append(getLine);
stringBuffer.append(entity.getValue());
stringBuffer.append(getLine);
}
for (Map.Entry<String,File> entity:fileMap.entrySet()) {
String name = "Content-Disposition: form-data; name=\""+fileName+"\"; filename=\""+entity.getValue().getName()+"\"";
stringBuffer.append(doubleBar+biaoshi);
stringBuffer.append(getLine);
stringBuffer.append(name);
stringBuffer.append(getLine);
stringBuffer.append(fileType);
stringBuffer.append(getLine);
stringBuffer.append(getLine);
File f = entity.getValue();
FileInputStream fileInputStream = new FileInputStream(f);
ByteArrayOutputStream byteArrayOutputStream = new ByteArrayOutputStream();
byte by[] = new byte[1024];
int k = 0;
while ((k=fileInputStream.read(by))!=-1){
byteArrayOutputStream.write(by,0,k);
}
by = byteArrayOutputStream.toByteArray();
for(int i = 0; i < by.length; i++){
stringBuffer.append(by[i]);
}
stringBuffer.append(getLine);
}
stringBuffer.append(doubleBar+biaoshi+doubleBar);
return stringBuffer.toString();
}
补充知识:java 如何取出传参数格式为form-data中的值
public Map<String, Object> Test(HttpServletRequest request,HttpServletRequest response) throws Exception {
Map<String, String> returnMap = new HashMap<String, String>();
String a=request.getParameter("a");//取出form-data中a的值
String b=request.getParameter("b");//取出form-data中a的值
//取出form-data中的二进制字段
MultipartHttpServletRequest multipartRequest=(MultipartHttpServletRequest) request;
MultipartFile multipartFile = multipartRequest.getFile("file");//file是form-data中二进制字段对应的name
System.out.println(multipartFile.getSize());
Map<String, Object> resultMapsReturn = new HashMap<>();
String imagePath="C:\\Users\\win\\Desktop\\1.jpg"//把取出来的二进制保存图片到本地
if(multipartFile.getSize()<=0){
resultMapsReturn.put("resultcode", "0");
resultMapsReturn.put("msg", DisWebConst.ERROR_TITLE);
}else{
InputStream is = multipartFile.getInputStream();
OutputStream out = new FileOutputStream(imagePath);
IOUtils.copy(is, out);
is.close();
out.close();
}
来源:https://blog.csdn.net/qq_33770498/article/details/80525182
标签:java,map,Multipart,form-data
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